6(d+1)=4(d+2)

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Solution for 6(d+1)=4(d+2) equation:


Simplifying
6(d + 1) = 4(d + 2)

Reorder the terms:
6(1 + d) = 4(d + 2)
(1 * 6 + d * 6) = 4(d + 2)
(6 + 6d) = 4(d + 2)

Reorder the terms:
6 + 6d = 4(2 + d)
6 + 6d = (2 * 4 + d * 4)
6 + 6d = (8 + 4d)

Solving
6 + 6d = 8 + 4d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4d' to each side of the equation.
6 + 6d + -4d = 8 + 4d + -4d

Combine like terms: 6d + -4d = 2d
6 + 2d = 8 + 4d + -4d

Combine like terms: 4d + -4d = 0
6 + 2d = 8 + 0
6 + 2d = 8

Add '-6' to each side of the equation.
6 + -6 + 2d = 8 + -6

Combine like terms: 6 + -6 = 0
0 + 2d = 8 + -6
2d = 8 + -6

Combine like terms: 8 + -6 = 2
2d = 2

Divide each side by '2'.
d = 1

Simplifying
d = 1

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