6(d+11)=4(d-5)

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Solution for 6(d+11)=4(d-5) equation: 



6(d+11)=4(d-5)

We move all terms to the left:

6(d+11)-(4(d-5))=0

We multiply parentheses

6d-(4(d-5))+66=0



We calculate terms in parentheses: -(4(d-5)), so:

4(d-5)

We multiply parentheses

4d-20

Back to the equation:

-(4d-20)



We get rid of parentheses

6d-4d+20+66=0

We add all the numbers together, and all the variables

2d+86=0

We move all terms containing d to the left, all other terms to the right

2d=-86

d=-86/2

d=-43

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