6(d+2)+d=28+6(d-1)

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Solution for 6(d+2)+d=28+6(d-1) equation:


Simplifying
6(d + 2) + d = 28 + 6(d + -1)

Reorder the terms:
6(2 + d) + d = 28 + 6(d + -1)
(2 * 6 + d * 6) + d = 28 + 6(d + -1)
(12 + 6d) + d = 28 + 6(d + -1)

Combine like terms: 6d + d = 7d
12 + 7d = 28 + 6(d + -1)

Reorder the terms:
12 + 7d = 28 + 6(-1 + d)
12 + 7d = 28 + (-1 * 6 + d * 6)
12 + 7d = 28 + (-6 + 6d)

Combine like terms: 28 + -6 = 22
12 + 7d = 22 + 6d

Solving
12 + 7d = 22 + 6d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-6d' to each side of the equation.
12 + 7d + -6d = 22 + 6d + -6d

Combine like terms: 7d + -6d = 1d
12 + 1d = 22 + 6d + -6d

Combine like terms: 6d + -6d = 0
12 + 1d = 22 + 0
12 + 1d = 22

Add '-12' to each side of the equation.
12 + -12 + 1d = 22 + -12

Combine like terms: 12 + -12 = 0
0 + 1d = 22 + -12
1d = 22 + -12

Combine like terms: 22 + -12 = 10
1d = 10

Divide each side by '1'.
d = 10

Simplifying
d = 10

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