6(d+2)=-8+2d

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Solution for 6(d+2)=-8+2d equation: 



6(d+2)=-8+2d

We move all terms to the left:

6(d+2)-(-8+2d)=0

We add all the numbers together, and all the variables

6(d+2)-(2d-8)=0

We multiply parentheses

6d-(2d-8)+12=0

We get rid of parentheses

6d-2d+8+12=0

We add all the numbers together, and all the variables

4d+20=0

We move all terms containing d to the left, all other terms to the right

4d=-20

d=-20/4

d=-5

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