6(d+2)=20+2d

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Solution for 6(d+2)=20+2d equation: 



6(d+2)=20+2d

We move all terms to the left:

6(d+2)-(20+2d)=0

We add all the numbers together, and all the variables

6(d+2)-(2d+20)=0

We multiply parentheses

6d-(2d+20)+12=0

We get rid of parentheses

6d-2d-20+12=0

We add all the numbers together, and all the variables

4d-8=0

We move all terms containing d to the left, all other terms to the right

4d=8

d=8/4

d=2

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