6(d+2)=4(d-6)

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Solution for 6(d+2)=4(d-6) equation: 



6(d+2)=4(d-6)

We move all terms to the left:

6(d+2)-(4(d-6))=0

We multiply parentheses

6d-(4(d-6))+12=0



We calculate terms in parentheses: -(4(d-6)), so:

4(d-6)

We multiply parentheses

4d-24

Back to the equation:

-(4d-24)



We get rid of parentheses

6d-4d+24+12=0

We add all the numbers together, and all the variables

2d+36=0

We move all terms containing d to the left, all other terms to the right

2d=-36

d=-36/2

d=-18

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