6(d+3)=4(d-1)

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Solution for 6(d+3)=4(d-1) equation: 



6(d+3)=4(d-1)

We move all terms to the left:

6(d+3)-(4(d-1))=0

We multiply parentheses

6d-(4(d-1))+18=0



We calculate terms in parentheses: -(4(d-1)), so:

4(d-1)

We multiply parentheses

4d-4

Back to the equation:

-(4d-4)



We get rid of parentheses

6d-4d+4+18=0

We add all the numbers together, and all the variables

2d+22=0

We move all terms containing d to the left, all other terms to the right

2d=-22

d=-22/2

d=-11

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