6(d+3)=9(d+9)

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Solution for 6(d+3)=9(d+9) equation: 



6(d+3)=9(d+9)

We move all terms to the left:

6(d+3)-(9(d+9))=0

We multiply parentheses

6d-(9(d+9))+18=0



We calculate terms in parentheses: -(9(d+9)), so:

9(d+9)

We multiply parentheses

9d+81

Back to the equation:

-(9d+81)



We get rid of parentheses

6d-9d-81+18=0

We add all the numbers together, and all the variables

-3d-63=0

We move all terms containing d to the left, all other terms to the right

-3d=63

d=63/-3

d=-21

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