6(d+4)+5=3(d-12)+2

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Solution for 6(d+4)+5=3(d-12)+2 equation: 



6(d+4)+5=3(d-12)+2

We move all terms to the left:

6(d+4)+5-(3(d-12)+2)=0

We multiply parentheses

6d-(3(d-12)+2)+24+5=0



We calculate terms in parentheses: -(3(d-12)+2), so:

3(d-12)+2

We multiply parentheses

3d-36+2

We add all the numbers together, and all the variables

3d-34

Back to the equation:

-(3d-34)



We add all the numbers together, and all the variables

6d-(3d-34)+29=0

We get rid of parentheses

6d-3d+34+29=0

We add all the numbers together, and all the variables

3d+63=0

We move all terms containing d to the left, all other terms to the right

3d=-63

d=-63/3

d=-21

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