6(d+4)=2(3d+12)

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Solution for 6(d+4)=2(3d+12) equation: 



6(d+4)=2(3d+12)

We move all terms to the left:

6(d+4)-(2(3d+12))=0

We multiply parentheses

6d-(2(3d+12))+24=0



We calculate terms in parentheses: -(2(3d+12)), so:

2(3d+12)

We multiply parentheses

6d+24

Back to the equation:

-(6d+24)



We get rid of parentheses

6d-6d-24+24=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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