6(d+5)=4(d-2)+2d

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Solution for 6(d+5)=4(d-2)+2d equation: 



6(d+5)=4(d-2)+2d

We move all terms to the left:

6(d+5)-(4(d-2)+2d)=0

We multiply parentheses

6d-(4(d-2)+2d)+30=0



We calculate terms in parentheses: -(4(d-2)+2d), so:

4(d-2)+2d

We add all the numbers together, and all the variables

2d+4(d-2)

We multiply parentheses

2d+4d-8

We add all the numbers together, and all the variables

6d-8

Back to the equation:

-(6d-8)



We get rid of parentheses

6d-6d+8+30=0

We add all the numbers together, and all the variables

38!=0

There is no solution for this equation

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