6(d+7)=2(d-2)+4d

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Solution for 6(d+7)=2(d-2)+4d equation: 



6(d+7)=2(d-2)+4d

We move all terms to the left:

6(d+7)-(2(d-2)+4d)=0

We multiply parentheses

6d-(2(d-2)+4d)+42=0



We calculate terms in parentheses: -(2(d-2)+4d), so:

2(d-2)+4d

We add all the numbers together, and all the variables

4d+2(d-2)

We multiply parentheses

4d+2d-4

We add all the numbers together, and all the variables

6d-4

Back to the equation:

-(6d-4)



We get rid of parentheses

6d-6d+4+42=0

We add all the numbers together, and all the variables

46!=0

There is no solution for this equation

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