6(d-1)+9=8(d+3)-3

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Solution for 6(d-1)+9=8(d+3)-3 equation: 



6(d-1)+9=8(d+3)-3

We move all terms to the left:

6(d-1)+9-(8(d+3)-3)=0

We multiply parentheses

6d-(8(d+3)-3)-6+9=0



We calculate terms in parentheses: -(8(d+3)-3), so:

8(d+3)-3

We multiply parentheses

8d+24-3

We add all the numbers together, and all the variables

8d+21

Back to the equation:

-(8d+21)



We add all the numbers together, and all the variables

6d-(8d+21)+3=0

We get rid of parentheses

6d-8d-21+3=0

We add all the numbers together, and all the variables

-2d-18=0

We move all terms containing d to the left, all other terms to the right

-2d=18

d=18/-2

d=-9

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