6(d-2)+8=4(d+1)+2

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Solution for 6(d-2)+8=4(d+1)+2 equation: 



6(d-2)+8=4(d+1)+2

We move all terms to the left:

6(d-2)+8-(4(d+1)+2)=0

We multiply parentheses

6d-(4(d+1)+2)-12+8=0



We calculate terms in parentheses: -(4(d+1)+2), so:

4(d+1)+2

We multiply parentheses

4d+4+2

We add all the numbers together, and all the variables

4d+6

Back to the equation:

-(4d+6)



We add all the numbers together, and all the variables

6d-(4d+6)-4=0

We get rid of parentheses

6d-4d-6-4=0

We add all the numbers together, and all the variables

2d-10=0

We move all terms containing d to the left, all other terms to the right

2d=10

d=10/2

d=5

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