6(d-8)-10=18(d+2)+2

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Solution for 6(d-8)-10=18(d+2)+2 equation: 



6(d-8)-10=18(d+2)+2

We move all terms to the left:

6(d-8)-10-(18(d+2)+2)=0

We multiply parentheses

6d-(18(d+2)+2)-48-10=0



We calculate terms in parentheses: -(18(d+2)+2), so:

18(d+2)+2

We multiply parentheses

18d+36+2

We add all the numbers together, and all the variables

18d+38

Back to the equation:

-(18d+38)



We add all the numbers together, and all the variables

6d-(18d+38)-58=0

We get rid of parentheses

6d-18d-38-58=0

We add all the numbers together, and all the variables

-12d-96=0

We move all terms containing d to the left, all other terms to the right

-12d=96

d=96/-12

d=-8

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