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6(e+15)3e=21
We move all terms to the left:
6(e+15)3e-(21)=0
We multiply parentheses
18e^2+270e-21=0
a = 18; b = 270; c = -21;
Δ = b2-4ac
Δ = 2702-4·18·(-21)
Δ = 74412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{74412}=\sqrt{36*2067}=\sqrt{36}*\sqrt{2067}=6\sqrt{2067}$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(270)-6\sqrt{2067}}{2*18}=\frac{-270-6\sqrt{2067}}{36} $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(270)+6\sqrt{2067}}{2*18}=\frac{-270+6\sqrt{2067}}{36} $
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