6(f+1)-3(f+2)=3(2f+3)+6

Solution for 6(f+1)-3(f+2)=3(2f+3)+6 equation:

Simplifying
6(f + 1) + -3(f + 2) = 3(2f + 3) + 6

Reorder the terms:
6(1 + f) + -3(f + 2) = 3(2f + 3) + 6
(1 * 6 + f * 6) + -3(f + 2) = 3(2f + 3) + 6
(6 + 6f) + -3(f + 2) = 3(2f + 3) + 6

Reorder the terms:
6 + 6f + -3(2 + f) = 3(2f + 3) + 6
6 + 6f + (2 * -3 + f * -3) = 3(2f + 3) + 6
6 + 6f + (-6 + -3f) = 3(2f + 3) + 6

Reorder the terms:
6 + -6 + 6f + -3f = 3(2f + 3) + 6

Combine like terms: 6 + -6 = 0
0 + 6f + -3f = 3(2f + 3) + 6
6f + -3f = 3(2f + 3) + 6

Combine like terms: 6f + -3f = 3f
3f = 3(2f + 3) + 6

Reorder the terms:
3f = 3(3 + 2f) + 6
3f = (3 * 3 + 2f * 3) + 6
3f = (9 + 6f) + 6

Reorder the terms:
3f = 9 + 6 + 6f

Combine like terms: 9 + 6 = 15
3f = 15 + 6f

Solving
3f = 15 + 6f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-6f' to each side of the equation.
3f + -6f = 15 + 6f + -6f

Combine like terms: 3f + -6f = -3f
-3f = 15 + 6f + -6f

Combine like terms: 6f + -6f = 0
-3f = 15 + 0
-3f = 15

Divide each side by '-3'.
f = -5

Simplifying
f = -5