6(f+1)-3(f+2)=3(n+2)

Solution for 6(f+1)-3(f+2)=3(n+2) equation:

Simplifying
6(f + 1) + -3(f + 2) = 3(n + 2)

Reorder the terms:
6(1 + f) + -3(f + 2) = 3(n + 2)
(1 * 6 + f * 6) + -3(f + 2) = 3(n + 2)
(6 + 6f) + -3(f + 2) = 3(n + 2)

Reorder the terms:
6 + 6f + -3(2 + f) = 3(n + 2)
6 + 6f + (2 * -3 + f * -3) = 3(n + 2)
6 + 6f + (-6 + -3f) = 3(n + 2)

Reorder the terms:
6 + -6 + 6f + -3f = 3(n + 2)

Combine like terms: 6 + -6 = 0
0 + 6f + -3f = 3(n + 2)
6f + -3f = 3(n + 2)

Combine like terms: 6f + -3f = 3f
3f = 3(n + 2)

Reorder the terms:
3f = 3(2 + n)
3f = (2 * 3 + n * 3)
3f = (6 + 3n)

Solving
3f = 6 + 3n

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by '3'.
f = 2 + n

Simplifying
f = 2 + n