6(f-1)=2(f+5)

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Solution for 6(f-1)=2(f+5) equation: 



6(f-1)=2(f+5)

We move all terms to the left:

6(f-1)-(2(f+5))=0

We multiply parentheses

6f-(2(f+5))-6=0



We calculate terms in parentheses: -(2(f+5)), so:

2(f+5)

We multiply parentheses

2f+10

Back to the equation:

-(2f+10)



We get rid of parentheses

6f-2f-10-6=0

We add all the numbers together, and all the variables

4f-16=0

We move all terms containing f to the left, all other terms to the right

4f=16

f=16/4

f=4

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