6(g+3)=2(g+23)

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Solution for 6(g+3)=2(g+23) equation: 



6(g+3)=2(g+23)

We move all terms to the left:

6(g+3)-(2(g+23))=0

We multiply parentheses

6g-(2(g+23))+18=0



We calculate terms in parentheses: -(2(g+23)), so:

2(g+23)

We multiply parentheses

2g+46

Back to the equation:

-(2g+46)



We get rid of parentheses

6g-2g-46+18=0

We add all the numbers together, and all the variables

4g-28=0

We move all terms containing g to the left, all other terms to the right

4g=28

g=28/4

g=7

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