6(g-3)+10=2(3g-4)

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Solution for 6(g-3)+10=2(3g-4) equation: 



6(g-3)+10=2(3g-4)

We move all terms to the left:

6(g-3)+10-(2(3g-4))=0

We multiply parentheses

6g-(2(3g-4))-18+10=0



We calculate terms in parentheses: -(2(3g-4)), so:

2(3g-4)

We multiply parentheses

6g-8

Back to the equation:

-(6g-8)



We add all the numbers together, and all the variables

6g-(6g-8)-8=0

We get rid of parentheses

6g-6g+8-8=0

We add all the numbers together, and all the variables

=0

g=0/1

g=0

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