6(g-72)=96

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Solution for 6(g-72)=96 equation: 



6(g-72)=96

We move all terms to the left:

6(g-72)-(96)=0

We multiply parentheses

6g-432-96=0

We add all the numbers together, and all the variables

6g-528=0

We move all terms containing g to the left, all other terms to the right

6g=528

g=528/6

g=88

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