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6(h+1/2-1=4h-8
We move all terms to the left:
6(h+1/2-1-(4h-8)=0
Domain of the equation: 2-1-(4h-8)!=0We multiply all the terms by the denominator
We move all terms containing h to the left, all other terms to the right
-(4h-8)!=-1
h∈R
6(h+1=0
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