6(h+2)-4(h-1)=3(h+2)

Solution for 6(h+2)-4(h-1)=3(h+2) equation:

6(h+2)-4(h-1)=3(h+2)

We move all terms to the left:

6(h+2)-4(h-1)-(3(h+2))=0

We multiply parentheses

6h-4h-(3(h+2))+12+4=0


We calculate terms in parentheses: -(3(h+2)), so:

3(h+2)

We multiply parentheses

3h+6

Back to the equation:

-(3h+6)


We add all the numbers together, and all the variables

2h-(3h+6)+16=0

We get rid of parentheses

2h-3h-6+16=0

We add all the numbers together, and all the variables

-1h+10=0

We move all terms containing h to the left, all other terms to the right

-h=-10

h=-10/-1

h=+10