6(j+2)-1=83

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Solution for 6(j+2)-1=83 equation: 



6(j+2)-1=83

We move all terms to the left:

6(j+2)-1-(83)=0

We add all the numbers together, and all the variables

6(j+2)-84=0

We multiply parentheses

6j+12-84=0

We add all the numbers together, and all the variables

6j-72=0

We move all terms containing j to the left, all other terms to the right

6j=72

j=72/6

j=12

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