6(j-2)+2(j-53)=2

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Solution for 6(j-2)+2(j-53)=2 equation: 



6(j-2)+2(j-53)=2

We move all terms to the left:

6(j-2)+2(j-53)-(2)=0

We multiply parentheses

6j+2j-12-106-2=0

We add all the numbers together, and all the variables

8j-120=0

We move all terms containing j to the left, all other terms to the right

8j=120

j=120/8

j=15

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