6(j-2)=2(9-2j)

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Solution for 6(j-2)=2(9-2j) equation: 



6(j-2)=2(9-2j)

We move all terms to the left:

6(j-2)-(2(9-2j))=0

We add all the numbers together, and all the variables

6(j-2)-(2(-2j+9))=0

We multiply parentheses

6j-(2(-2j+9))-12=0



We calculate terms in parentheses: -(2(-2j+9)), so:

2(-2j+9)

We multiply parentheses

-4j+18

Back to the equation:

-(-4j+18)



We get rid of parentheses

6j+4j-18-12=0

We add all the numbers together, and all the variables

10j-30=0

We move all terms containing j to the left, all other terms to the right

10j=30

j=30/10

j=3

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