6(k+1)-5(k+2)=0

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Solution for 6(k+1)-5(k+2)=0 equation:


Simplifying
6(k + 1) + -5(k + 2) = 0

Reorder the terms:
6(1 + k) + -5(k + 2) = 0
(1 * 6 + k * 6) + -5(k + 2) = 0
(6 + 6k) + -5(k + 2) = 0

Reorder the terms:
6 + 6k + -5(2 + k) = 0
6 + 6k + (2 * -5 + k * -5) = 0
6 + 6k + (-10 + -5k) = 0

Reorder the terms:
6 + -10 + 6k + -5k = 0

Combine like terms: 6 + -10 = -4
-4 + 6k + -5k = 0

Combine like terms: 6k + -5k = 1k
-4 + 1k = 0

Solving
-4 + 1k = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 1k = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 1k = 0 + 4
1k = 0 + 4

Combine like terms: 0 + 4 = 4
1k = 4

Divide each side by '1'.
k = 4

Simplifying
k = 4

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