6(k+1)=3+6k+3

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Solution for 6(k+1)=3+6k+3 equation: 



6(k+1)=3+6k+3

We move all terms to the left:

6(k+1)-(3+6k+3)=0

We add all the numbers together, and all the variables

6(k+1)-(6k+6)=0

We multiply parentheses

6k-(6k+6)+6=0

We get rid of parentheses

6k-6k-6+6=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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