6(k+2)+12+1=13

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Solution for 6(k+2)+12+1=13 equation: 



6(k+2)+12+1=13

We move all terms to the left:

6(k+2)+12+1-(13)=0

We add all the numbers together, and all the variables

6(k+2)=0

We multiply parentheses

6k+12=0

We move all terms containing k to the left, all other terms to the right

6k=-12

k=-12/6

k=-2

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