6(k+2)+1=18

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Solution for 6(k+2)+1=18 equation: 



6(k+2)+1=18

We move all terms to the left:

6(k+2)+1-(18)=0

We add all the numbers together, and all the variables

6(k+2)-17=0

We multiply parentheses

6k+12-17=0

We add all the numbers together, and all the variables

6k-5=0

We move all terms containing k to the left, all other terms to the right

6k=5

k=5/6

k=5/6

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