6(k+2)+1=3

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Solution for 6(k+2)+1=3 equation: 



6(k+2)+1=3

We move all terms to the left:

6(k+2)+1-(3)=0

We add all the numbers together, and all the variables

6(k+2)-2=0

We multiply parentheses

6k+12-2=0

We add all the numbers together, and all the variables

6k+10=0

We move all terms containing k to the left, all other terms to the right

6k=-10

k=-10/6

k=-1+2/3

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