6(k+2)+4=13

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Solution for 6(k+2)+4=13 equation: 



6(k+2)+4=13

We move all terms to the left:

6(k+2)+4-(13)=0

We add all the numbers together, and all the variables

6(k+2)-9=0

We multiply parentheses

6k+12-9=0

We add all the numbers together, and all the variables

6k+3=0

We move all terms containing k to the left, all other terms to the right

6k=-3

k=-3/6

k=-1/2

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