6(k+2)-4(k+3)=7

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Solution for 6(k+2)-4(k+3)=7 equation: 


Simplifying
6(k + 2) + -4(k + 3) = 7

Reorder the terms:
6(2 + k) + -4(k + 3) = 7
(2 * 6 + k * 6) + -4(k + 3) = 7
(12 + 6k) + -4(k + 3) = 7

Reorder the terms:
12 + 6k + -4(3 + k) = 7
12 + 6k + (3 * -4 + k * -4) = 7
12 + 6k + (-12 + -4k) = 7

Reorder the terms:
12 + -12 + 6k + -4k = 7

Combine like terms: 12 + -12 = 0
0 + 6k + -4k = 7
6k + -4k = 7

Combine like terms: 6k + -4k = 2k
2k = 7

Solving
2k = 7

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Divide each side by '2'.
k = 3.5

Simplifying
k = 3.5

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