6(k+2)2k-5)=22

Solution for 6(k+2)2k-5)=22 equation:

6(k+2)2k-5)=22

We move all terms to the left:

6(k+2)2k-5)-(22)=0

We add all the numbers together, and all the variables

6(k+2)2k=0

We multiply parentheses

12k^2+24k=0

a = 12; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·12·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*12}=\frac{-48}{24}
=-2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*12}=\frac{0}{24}
=0
$