6(k+2)=+1=13

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Solution for 6(k+2)=+1=13 equation: 



6(k+2)=+1=13

We move all terms to the left:

6(k+2)-(+1)=0

We add all the numbers together, and all the variables

6(k+2)-1=0

We multiply parentheses

6k+12-1=0

We add all the numbers together, and all the variables

6k+11=0

We move all terms containing k to the left, all other terms to the right

6k=-11

k=-11/6

k=-1+5/6

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