6(k+2)=-4(-k+4)

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Solution for 6(k+2)=-4(-k+4) equation: 



6(k+2)=-4(-k+4)

We move all terms to the left:

6(k+2)-(-4(-k+4))=0

We add all the numbers together, and all the variables

6(k+2)-(-4(-1k+4))=0

We multiply parentheses

6k-(-4(-1k+4))+12=0



We calculate terms in parentheses: -(-4(-1k+4)), so:

-4(-1k+4)

We multiply parentheses

4k-16

Back to the equation:

-(4k-16)



We get rid of parentheses

6k-4k+16+12=0

We add all the numbers together, and all the variables

2k+28=0

We move all terms containing k to the left, all other terms to the right

2k=-28

k=-28/2

k=-14

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