6(k+2)=-4(-k+4)

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Solution for 6(k+2)=-4(-k+4) equation:



6(k+2)=-4(-k+4)
We move all terms to the left:
6(k+2)-(-4(-k+4))=0
We add all the numbers together, and all the variables
6(k+2)-(-4(-1k+4))=0
We multiply parentheses
6k-(-4(-1k+4))+12=0
We calculate terms in parentheses: -(-4(-1k+4)), so:
-4(-1k+4)
We multiply parentheses
4k-16
Back to the equation:
-(4k-16)
We get rid of parentheses
6k-4k+16+12=0
We add all the numbers together, and all the variables
2k+28=0
We move all terms containing k to the left, all other terms to the right
2k=-28
k=-28/2
k=-14

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