6(k+2)=32

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Solution for 6(k+2)=32 equation: 



6(k+2)=32

We move all terms to the left:

6(k+2)-(32)=0

We multiply parentheses

6k+12-32=0

We add all the numbers together, and all the variables

6k-20=0

We move all terms containing k to the left, all other terms to the right

6k=20

k=20/6

k=3+1/3

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