6(k+5)-3k=6-2(2k+2)

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Solution for 6(k+5)-3k=6-2(2k+2) equation: 



6(k+5)-3k=6-2(2k+2)

We move all terms to the left:

6(k+5)-3k-(6-2(2k+2))=0

We add all the numbers together, and all the variables

-3k+6(k+5)-(6-2(2k+2))=0

We multiply parentheses

-3k+6k-(6-2(2k+2))+30=0



We calculate terms in parentheses: -(6-2(2k+2)), so:

6-2(2k+2)

determiningTheFunctionDomain
-2(2k+2)+6

We multiply parentheses

-4k-4+6

We add all the numbers together, and all the variables

-4k+2

Back to the equation:

-(-4k+2)



We add all the numbers together, and all the variables

3k-(-4k+2)+30=0

We get rid of parentheses

3k+4k-2+30=0

We add all the numbers together, and all the variables

7k+28=0

We move all terms containing k to the left, all other terms to the right

7k=-28

k=-28/7

k=-4

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