6(k+7)=3(k-1)

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Solution for 6(k+7)=3(k-1) equation:



6(k+7)=3(k-1)
We move all terms to the left:
6(k+7)-(3(k-1))=0
We multiply parentheses
6k-(3(k-1))+42=0
We calculate terms in parentheses: -(3(k-1)), so:
3(k-1)
We multiply parentheses
3k-3
Back to the equation:
-(3k-3)
We get rid of parentheses
6k-3k+3+42=0
We add all the numbers together, and all the variables
3k+45=0
We move all terms containing k to the left, all other terms to the right
3k=-45
k=-45/3
k=-15

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