6(k-1)=3k+6

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Solution for 6(k-1)=3k+6 equation: 



6(k-1)=3k+6

We move all terms to the left:

6(k-1)-(3k+6)=0

We multiply parentheses

6k-(3k+6)-6=0

We get rid of parentheses

6k-3k-6-6=0

We add all the numbers together, and all the variables

3k-12=0

We move all terms containing k to the left, all other terms to the right

3k=12

k=12/3

k=4

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