6(k-12)=2(-10+6k)+8

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Solution for 6(k-12)=2(-10+6k)+8 equation: 



6(k-12)=2(-10+6k)+8

We move all terms to the left:

6(k-12)-(2(-10+6k)+8)=0

We add all the numbers together, and all the variables

6(k-12)-(2(6k-10)+8)=0

We multiply parentheses

6k-(2(6k-10)+8)-72=0



We calculate terms in parentheses: -(2(6k-10)+8), so:

2(6k-10)+8

We multiply parentheses

12k-20+8

We add all the numbers together, and all the variables

12k-12

Back to the equation:

-(12k-12)



We get rid of parentheses

6k-12k+12-72=0

We add all the numbers together, and all the variables

-6k-60=0

We move all terms containing k to the left, all other terms to the right

-6k=60

k=60/-6

k=-10

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