6(k-2)-7=6k-(5k-1)

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Solution for 6(k-2)-7=6k-(5k-1) equation: 



6(k-2)-7=6k-(5k-1)

We move all terms to the left:

6(k-2)-7-(6k-(5k-1))=0

We multiply parentheses

6k-(6k-(5k-1))-12-7=0



We calculate terms in parentheses: -(6k-(5k-1)), so:

6k-(5k-1)

We get rid of parentheses

6k-5k+1

We add all the numbers together, and all the variables

k+1

Back to the equation:

-(k+1)



We add all the numbers together, and all the variables

6k-(k+1)-19=0

We get rid of parentheses

6k-k-1-19=0

We add all the numbers together, and all the variables

5k-20=0

We move all terms containing k to the left, all other terms to the right

5k=20

k=20/5

k=4

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