6(k-2)-8=5k-(4K-2)

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Solution for 6(k-2)-8=5k-(4K-2) equation: 



6(k-2)-8=5k-(4-2)

We move all terms to the left:

6(k-2)-8-(5k-(4-2))=0

We add all the numbers together, and all the variables

6(k-2)-(5k-2)-8=0

We multiply parentheses

6k-(5k-2)-12-8=0

We get rid of parentheses

6k-5k+2-12-8=0

We add all the numbers together, and all the variables

k-18=0

We move all terms containing k to the left, all other terms to the right

k=18

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