6(k-3)+5k=k+32

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Solution for 6(k-3)+5k=k+32 equation:



6(k-3)+5k=k+32
We move all terms to the left:
6(k-3)+5k-(k+32)=0
We add all the numbers together, and all the variables
5k+6(k-3)-(k+32)=0
We multiply parentheses
5k+6k-(k+32)-18=0
We get rid of parentheses
5k+6k-k-32-18=0
We add all the numbers together, and all the variables
10k-50=0
We move all terms containing k to the left, all other terms to the right
10k=50
k=50/10
k=5

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