6(k-3)-5(k+2)-10=

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Solution for 6(k-3)-5(k+2)-10= equation:


Simplifying
6(k + -3) + -5(k + 2) + -10 = 0

Reorder the terms:
6(-3 + k) + -5(k + 2) + -10 = 0
(-3 * 6 + k * 6) + -5(k + 2) + -10 = 0
(-18 + 6k) + -5(k + 2) + -10 = 0

Reorder the terms:
-18 + 6k + -5(2 + k) + -10 = 0
-18 + 6k + (2 * -5 + k * -5) + -10 = 0
-18 + 6k + (-10 + -5k) + -10 = 0

Reorder the terms:
-18 + -10 + -10 + 6k + -5k = 0

Combine like terms: -18 + -10 = -28
-28 + -10 + 6k + -5k = 0

Combine like terms: -28 + -10 = -38
-38 + 6k + -5k = 0

Combine like terms: 6k + -5k = 1k
-38 + 1k = 0

Solving
-38 + 1k = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '38' to each side of the equation.
-38 + 38 + 1k = 0 + 38

Combine like terms: -38 + 38 = 0
0 + 1k = 0 + 38
1k = 0 + 38

Combine like terms: 0 + 38 = 38
1k = 38

Divide each side by '1'.
k = 38

Simplifying
k = 38

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