6(k-3)-5=3k-(2k-1)

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Solution for 6(k-3)-5=3k-(2k-1) equation:


Simplifying
6(k + -3) + -5 = 3k + -1(2k + -1)

Reorder the terms:
6(-3 + k) + -5 = 3k + -1(2k + -1)
(-3 * 6 + k * 6) + -5 = 3k + -1(2k + -1)
(-18 + 6k) + -5 = 3k + -1(2k + -1)

Reorder the terms:
-18 + -5 + 6k = 3k + -1(2k + -1)

Combine like terms: -18 + -5 = -23
-23 + 6k = 3k + -1(2k + -1)

Reorder the terms:
-23 + 6k = 3k + -1(-1 + 2k)
-23 + 6k = 3k + (-1 * -1 + 2k * -1)
-23 + 6k = 3k + (1 + -2k)

Reorder the terms:
-23 + 6k = 1 + 3k + -2k

Combine like terms: 3k + -2k = 1k
-23 + 6k = 1 + 1k

Solving
-23 + 6k = 1 + 1k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-1k' to each side of the equation.
-23 + 6k + -1k = 1 + 1k + -1k

Combine like terms: 6k + -1k = 5k
-23 + 5k = 1 + 1k + -1k

Combine like terms: 1k + -1k = 0
-23 + 5k = 1 + 0
-23 + 5k = 1

Add '23' to each side of the equation.
-23 + 23 + 5k = 1 + 23

Combine like terms: -23 + 23 = 0
0 + 5k = 1 + 23
5k = 1 + 23

Combine like terms: 1 + 23 = 24
5k = 24

Divide each side by '5'.
k = 4.8

Simplifying
k = 4.8

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