6(k-3)=2(3k+4)

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Solution for 6(k-3)=2(3k+4) equation: 



6(k-3)=2(3k+4)

We move all terms to the left:

6(k-3)-(2(3k+4))=0

We multiply parentheses

6k-(2(3k+4))-18=0



We calculate terms in parentheses: -(2(3k+4)), so:

2(3k+4)

We multiply parentheses

6k+8

Back to the equation:

-(6k+8)



We get rid of parentheses

6k-6k-8-18=0

We add all the numbers together, and all the variables

-26!=0

There is no solution for this equation

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