6(k-3)=2(k+5)

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Solution for 6(k-3)=2(k+5) equation: 



6(k-3)=2(k+5)

We move all terms to the left:

6(k-3)-(2(k+5))=0

We multiply parentheses

6k-(2(k+5))-18=0



We calculate terms in parentheses: -(2(k+5)), so:

2(k+5)

We multiply parentheses

2k+10

Back to the equation:

-(2k+10)



We get rid of parentheses

6k-2k-10-18=0

We add all the numbers together, and all the variables

4k-28=0

We move all terms containing k to the left, all other terms to the right

4k=28

k=28/4

k=7

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