6(k-5)=2(10+3k)

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Solution for 6(k-5)=2(10+3k) equation: 



6(k-5)=2(10+3k)

We move all terms to the left:

6(k-5)-(2(10+3k))=0

We add all the numbers together, and all the variables

6(k-5)-(2(3k+10))=0

We multiply parentheses

6k-(2(3k+10))-30=0



We calculate terms in parentheses: -(2(3k+10)), so:

2(3k+10)

We multiply parentheses

6k+20

Back to the equation:

-(6k+20)



We get rid of parentheses

6k-6k-20-30=0

We add all the numbers together, and all the variables

-50!=0

There is no solution for this equation

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